Last updated 5 years ago
13ā2=>32==9 \frac {1}{3^{-2}} => 3^2 == 93ā21ā=>32==9 and 13ā1=>31==3 \frac {1}{3^{-1}} => 3^1 == 3 3ā11ā=>31==3
In both cases the minus is cancelling it out
If you have logā”(10)=1.5d\log(10) = 1.5dlog(10)=1.5d, this becomes logā”(10)1.5=d\frac{\log(10)}{1.5}=d1.5log(10)ā=d
If you have log(10)=0.1dlog(10) = 0.1dlog(10)=0.1d, this becomes 10logā”(10)=d10\log(10) = d10log(10)=d
if you have log(10)=d2log(10)=\frac{d}{2}log(10)=2dā, this becomes 2logā”(10)=d2\log(10)=d2log(10)=d
